Java Challenge - diff21

Given an int n, return the absolute difference between n and 21, except return double the absolute difference if n is over 21.

diff21(19) → 2
diff21(10) → 11
diff21(21) → 0
Hisoka's Sol:

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public int diff21(int n) { if(n <= 21) return 21-n; else { return 2*Math.abs(n-21); } }

Result:

Codingbat Sol:

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public int diff21(int n) { if (n <= 21) { return 21 - n; } else { return (n - 21) * 2; } }

Java Challenge - sumDouble

Given two int values, return their sum. Unless the two values are the same, then return double their sum.

sumDouble(1, 2) → 3
sumDouble(3, 2) → 5
sumDouble(2, 2) → 8

Hisoka's Solution :

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public int sumDouble(int a, int b) { if(a == b) return (a+b)*2; else return a+b; }

Result:

Codingbat Solution:

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public int sumDouble(int a, int b) { // Store the sum in a local variable int sum = a + b; // Double it if a and b are the same if (a == b) { sum = sum * 2; } return sum; }