Java Challenge - delDel - warm_up

Given a string, if the string "del" appears starting at index 1, return a string where that "del" has been deleted. Otherwise, return the string unchanged. delDel("adelbc") → "abc" delDel("adelHello") → "aHello" delDel("adedbc") → "adedbc"

Hisoka's way :

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public String delDel(String str) { if(str.length() <= 3) return str; else if(str.substring(1, 4).equalsIgnoreCase("del"))return str.replace("del", ""); else return str; }

Result:

Codingbat answer:

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public String delDel(String str) { if (str.length()>=4 && str.substring(1, 4).equals("del")) { // First char + rest of string starting at 4 return str.substring(0, 1) + str.substring(4); } // Otherwise return the original string. return str; }

Java Challenge - lastDigit - warm_up

Given two non-negative int values, return true if they have the same last digit, such as with 27 and 57. Note that the % "mod" operator computes remainders, so 17 % 10 is 7.

lastDigit(7, 17) → true
lastDigit(6, 17) → false
lastDigit(3, 113) → true

Hisoka's Answer:

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public boolean lastDigit(int a, int b) { if(a%10 == b%10) return true; else return false; }

Result:

Codingbat Answer:

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public boolean lastDigit(int a, int b) { // True if the last digits are the same return(a % 10 == b % 10); }