Java Challenge - nearHundred - warm_up

Given an int n, return true if it is within 10 of 100 or 200. Note: Math.abs(num) computes the absolute value of a number. nearHundred(93) → true nearHundred(90) → true nearHundred(89) → false

Hisoka's code:

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public boolean nearHundred(int n) { return((Math.abs(n-100) <= 10)||(Math.abs(200-n) <= 10)); }

Output:

Codingbat code:

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public boolean nearHundred(int n) { return ((Math.abs(100 - n) <= 10) || (Math.abs(200 - n) <= 10)); }

Hohoho... Mirip... :D